진행시각 | 교재쪽 | 제목 | 설명 | | 14초 | 20쪽 | 삼각함수 사이의 관계 | 삼각함수 사이의 관계
① , ,![[tex]cot heta=frac{1}{ an heta}[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_uNAYHJBBZdtomgjlY_E4y2GFRDv2h-D78Iqh6nDwpjHf5gQXZF2C-ecCA6Z2LKQpl5mO6qzVNnoXcoaGtnAdliU46DmCiX7VpxiFxpF9bVSIBMrcNGfwTbLUVCruWybvolL5Stz-VKjDs1ty9aBvGFqPTNnU5VM79UOx8YLwA=s0-d)
[cscθ = 1/sinθ, secθ = 1/cosθ, cotθ = 1/tanθ]
② , ![[tex]cot heta=frac{cos heta}{sin heta}[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_utqOYmOvScik3jSg8vFHWh9-_9gzD_qHNVmAuKwbPnYg96UilrQChceL4AvUhpC22V_f8E5upPB2DrWUBrltsW_-4esaAv6Bsjmi45rrfJZiaRxYX5Uz3cLwl4xxA__iEez2hxrCuvZz8VD4SducxtDbDSU6H6aJL202YVHMbQgFazAYL9yERF-tpLIQ=s0-d)
[tanθ = sinθ/cosθ, cotθ = cosθ/sinθ]
③ ![[tex]sin^2 heta+cos^2 heta=1[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_tmADiOywN4Dvd4CB6MczLSKa-fF7ukgHf4dusDUIh8tK-O0Ya2KqjJ1-Hv2_ROUuFI9G1W-VnGvixrm8UXdAi25s_DvuGJiGsrh1SqZ4p4EHVDaFZU7mwHJF8LeHX1fIHB-4tfnUrCb0_She1qKm776aVaXmE=s0-d)
[sin^2θ + cos^2θ=1]
④ , ![[tex]1+cot^2 heta=csc^2 heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_vx2J51EH4FhnxKTNUVS6AB1VctCqPGIsozoMomR1kNCy4kmtKueqSU8s8ejJM3g_vQqMSF-7_wou7OCqOTJo4h3Jk1s56SDpPuH3LXg8W1RvAz5TRrbZKDbNg9ajEJnjEiK3btlZUyqJ1kZlGVyT8=s0-d)
[ tan^2θ+1 = sec^2θ, 1+cot^2θ = csc^2θ] | | 9분 20초 | 21쪽 | 예제1) | [sinθ+cosθ=1/√2]일 때, 다음 식의 값을 구하여라.
(1) [sinθcosθ]
(2) [cos^3θ + sin^3θ ]
(3) [tanθ + cotθ]
| | 17분 29초 | 22쪽 | 예제2) | 이차방정식 [2x^2+px-1=0]의 두 근이 sinθ, cosθ 일 때, 상수 p의 값을 구하여라. | | 20분 6초 | 23쪽 | 예제3) | [sinθ+cosθ = (1-√3)/2]일 때, sinθ, cosθ 를 두 근으로 하는 x에 대한 이차방정식을 구하여라.
| | 23분 50초 | 23쪽 | 여러 가지 각의 삼각함수 | (1) 2nπ+θ의 삼각함수(단, n은 정수)
①![[tex]sin(2npi+ heta)=sin heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_tu4jTcl8SYxRckC1V2KvbDM12W5w0fXUoY9yZKdagYTGKZmWt0M2BZ3q2Cb1077-7KG-oRO3Eu8zw6jvTN6INHJFfiF9RU7OD69FeitwGb3uVrDlxTffzyjTic9-PM4pXjR5ICyfGLEptSgMVUv1tgZQX-H7A=s0-d)
[sin(2nπ+θ)=sinθ]
② ![[tex]cos(2npi+ heta)=cos heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_ugGfGFCtlTDyjChZA1OumJCN5IgEpMDr6mM-SDHkdXyoA1tY-8oayJeQ8nSZuRy8hCnE_Ncd81QcKXQAITofP1Oa1gAKYvYySSZfM4wubZ7BWjJVcAwDB8F3rfFpMPfOAGyNcY_c9vqntcJZHaurNGtA=s0-d)
[cos(2nπ+θ)=cosθ]
③ ![[tex] an(2npi+ heta)= an heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_uw3n3efyJUL_Rfnbko-UQVYRHPcc6ijlCXS2Sww2OExXVJpioHS6jSKhMFSZhOjP-HjReKb3ZQeBiT0VijOqQhFyzpoeNWZjlvo0DwJvcaH3Thw9mgjJ7l8jWQmYtcO6df3XKVRglYIak1AD7xKOqz1jEMcU0=s0-d)
[tan(2nπ+θ)=tanθ]
(2) -θ의 삼각함수
④ ![[tex]sin(- heta)=-sin heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_tp2Y8I20YzYbYM1wiDT5mo3J_ynlSApst788e-Wmcy61xEu1ZQxlavuXQThr-CYH3we1qMLv1ehsT4hBQIDj_pY5roRUHWwduenRNWvA5l2FDrjKqsEZJBGzMFwdfOBOruza3I25Pu4lHNIYQb1Fg=s0-d)
[sin(-θ)=-sinθ]
⑤ ![[tex]cos(- heta)=cos heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_v5Cx0-9xdOweQJ0UsPtB4netgoeLykyyqeFgYnw4NpZfL66qroQZCN81nEkGf-YofSz8D4YBBkRdt8sPBredV8iGSwIFCTTCKzzSaAlPSnKDS6KweXDDyIt1Tr60sQ8ye-jdlm9FwnUK-GCw=s0-d)
[cos(-θ)=cosθ]
⑥ ![[tex] an(- heta)=- an heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_u-LjhK92a8vN8RS7AyJUToaW0QZjvhvoxwr38GX3TReTd-svn6F2UOfbcEoUj_Z94LYv1gR4XL4BbkVcAGdPRjqduOkarkT1S7n73Ie23e21SwbE7n6NhpSIJ8dyvOnBi6gr-0TI6hXTOMa9Va9w=s0-d)
[tan(-θ)=-tanθ] | | 51분 6초 | 29쪽 | 예제1) | 다음 삼각함수의 값을 구하여라.
(1) [cos 15/4 π ]
(2) [sin 3/4 π ]
(3) [cos 7/6 π ]
(4) tan 150° | | 55분 15초 | 30쪽 | 삼각함수 사이의 관계 보충설명 | | | 1시간 1분 | 30쪽 | 예제2) | 다음 식의 값을 구하여라.
(1) sin50° + tan110° + cos140° + cot200°
(2) (sin10° + cos10° )2 + (sin80° - cos80°)2
(3) tan(20° + θ) · tan(70° - θ) | |
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