진행시각 | 교재쪽 | 제목 | 설명 | | 14초 | 20쪽 | 삼각함수 사이의 관계 | 삼각함수 사이의 관계
① , ,![[tex]cot heta=frac{1}{ an heta}[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_v8Ai1n7B_ueb4t1ik_K_FJtBMOuHjUZoNMPwUt-S6cFJ4PdTviV-Kma8LbyLfP0iBXDA5TMJRxa3qyMSW23IOScnU-g_alDn9yiBKr3N8hfYqw5aAvqzi6Oyzeaofmmk7CSLdubI9aIwLlJWWZKMRQaGizrjgjH84CUPywXiM=s0-d)
[cscθ = 1/sinθ, secθ = 1/cosθ, cotθ = 1/tanθ]
② , ![[tex]cot heta=frac{cos heta}{sin heta}[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_t_1tySKrC54mPBUdFw3Dxx-faFG849JkUdrv1VWgn7I4JIm-lpFfyQZQZ0iwsyD7GSPar8TI1e5GbYVtuhwAZCmyh9g82iX3pL328_6XHEfF3EWNzLEyDZdMvN_CU3Qk7Gf81QysLZP78qzX3ZmlTuV1M-FQeEFKgw-dy04VUoxP3fEei-3lO7vFTlqg=s0-d)
[tanθ = sinθ/cosθ, cotθ = cosθ/sinθ]
③ ![[tex]sin^2 heta+cos^2 heta=1[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_sqUZ6EQL_ev2wVIG5TnzA4rxPzvXYOoBkdsVebTF8La8mCMlFL4npCuASM9kdEX-wiDrKLvn5EvY2jv3BNiWqyYKD-Tidmrs4kCO_8rCLSkrE_T7lW_tyZblbSU1e31BSAFwVM-AzWziIrU-QThD47ssVAn1M=s0-d)
[sin^2θ + cos^2θ=1]
④ , ![[tex]1+cot^2 heta=csc^2 heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_tHYFnIwodOCqYuDGA48awrHiUaaGDoTxKPzLU1XzCR12FP3eJZ0Th38StoSg9fKf6L95WviIeOIm2Sijtq1OkO2l9sThMGXZNDLpMNI7VVWhPwEwjZV064Xpv2JqK1FNZIJZVn8dqBKD7nyyUIpGQ=s0-d)
[ tan^2θ+1 = sec^2θ, 1+cot^2θ = csc^2θ] | | 9분 20초 | 21쪽 | 예제1) | [sinθ+cosθ=1/√2]일 때, 다음 식의 값을 구하여라.
(1) [sinθcosθ]
(2) [cos^3θ + sin^3θ ]
(3) [tanθ + cotθ]
| | 17분 29초 | 22쪽 | 예제2) | 이차방정식 [2x^2+px-1=0]의 두 근이 sinθ, cosθ 일 때, 상수 p의 값을 구하여라. | | 20분 6초 | 23쪽 | 예제3) | [sinθ+cosθ = (1-√3)/2]일 때, sinθ, cosθ 를 두 근으로 하는 x에 대한 이차방정식을 구하여라.
| | 23분 50초 | 23쪽 | 여러 가지 각의 삼각함수 | (1) 2nπ+θ의 삼각함수(단, n은 정수)
①![[tex]sin(2npi+ heta)=sin heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_sifQXni4sBaNapFc_2SVucDqMKSKB90w_-9xeq2mFk6xHFsp22q9G-qkogQIsWRZhvAiwMP_lGJymPo_X6IhhDhQvDC6c9k9IjeR-0bEZvZLFNZxn3w2zj6yYHL73MgtUOPqzS-yviQHfPuKKvfQ7gYVz-_mo=s0-d)
[sin(2nπ+θ)=sinθ]
② ![[tex]cos(2npi+ heta)=cos heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_tBhDaOLuY9Wcq1Fb8cJf-E5T3IKJ7mYWxlr2C_n-0tF2LcPt0CR6oY4JFu3t6CdXkCueYc674pBif1lRYv1MW_rDLlRwS0TxsptAQ8zerXeYgEn-pRNnul2dxZb39PjEOQXj0kX9wRZWTe4nHELiPjeA=s0-d)
[cos(2nπ+θ)=cosθ]
③ ![[tex] an(2npi+ heta)= an heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_uSJgsQ60K7bWRpjjClhWGvPpnXKfp3WZyOCihxj_rQ59yOgbW4FJV_7T8deVFtWj9LT5wYrMzAP0sbL6dDbB8pXJ39Jf-0DTZGq0eZQczdkNS3GM3FOppkTamupMlcWv5nBnYDWNzFHpD7_io0q--kackD1TI=s0-d)
[tan(2nπ+θ)=tanθ]
(2) -θ의 삼각함수
④ ![[tex]sin(- heta)=-sin heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_voQPevacmv5GP07mAbZZm9ZpvJ3CKLIiF2l0AOGEH0I3oZgEnrn-vdCfAdZ5aPcSkt1HG_YBMKzqkG20g6TvrrDBu8IW-JCn2G4gdor2hJzUXi02oAuYratJdsxEz-XMyZ26wZhslRKUbvV1Jh-1s=s0-d)
[sin(-θ)=-sinθ]
⑤ ![[tex]cos(- heta)=cos heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_sGqTNCaTOmpqyYGjbYD6WAIBKDocw3l3P3qPpOcRPxlsO4qPDdwlX8vWcZF-2by3fB8Vyew6rTjtkiQKJnsDbZ0oP1BIGYWlNYGG6zTGXMkMTfXRa0H-b991cSX76Vx3ohWffaH5jnISbAfA=s0-d)
[cos(-θ)=cosθ]
⑥ ![[tex] an(- heta)=- an heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_u7LNFbPyK-I-9he9RIda1ol3JVPTlQkamFbWXfc4blgXEdFsPRXhnq-PDBz5mS-RSgR73GwJOnjMajodpxZFpgCouZsKyCGGKWtFfKoPrKMXelIiNg1ajtVwR6uYn7gmdD5Cm9xfnk3xmec4-5Zg=s0-d)
[tan(-θ)=-tanθ] | | 51분 6초 | 29쪽 | 예제1) | 다음 삼각함수의 값을 구하여라.
(1) [cos 15/4 π ]
(2) [sin 3/4 π ]
(3) [cos 7/6 π ]
(4) tan 150° | | 55분 15초 | 30쪽 | 삼각함수 사이의 관계 보충설명 | | | 1시간 1분 | 30쪽 | 예제2) | 다음 식의 값을 구하여라.
(1) sin50° + tan110° + cos140° + cot200°
(2) (sin10° + cos10° )2 + (sin80° - cos80°)2
(3) tan(20° + θ) · tan(70° - θ) | |
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