진행시각 | 교재쪽 | 제목 | 설명 | | 14초 | 20쪽 | 삼각함수 사이의 관계 | 삼각함수 사이의 관계
① , ,![[tex]cot heta=frac{1}{ an heta}[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_vcwGA_5aA5lbeWYiM-b5zaF8os9AdkUeSqQDjSJNP2czbkHDqAh84pV0dfHMk7F5pCzez_2XXrv5sD_55mIZHPugYVxG2G4n7KU_d_yvMWpDuWSZBATAf3lmNMOVg-H0HD6DIBJlNmfY9UdRZnMbBwHUWIH7L3umounNq8FhA=s0-d)
[cscθ = 1/sinθ, secθ = 1/cosθ, cotθ = 1/tanθ]
② , ![[tex]cot heta=frac{cos heta}{sin heta}[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_tdaj5uL6L60DZMYi5mFpr4Uny_g6imzW2wXsH9Xy2hjqwunJU2p8_v0OuUmGw3DK48ce3sLsJgnoZUcYjC-cuyJXF4NWLbWIjVS6ADJAlG4Y9sGW5gvPYkh75bNX2fyedXwcIU53CeJ5J7sOX6bLpp2EnznNRJY7wAs84ACn_Tzp8ekcM8Gs59RpAOtw=s0-d)
[tanθ = sinθ/cosθ, cotθ = cosθ/sinθ]
③ ![[tex]sin^2 heta+cos^2 heta=1[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_vMk66z5s9EUsqrdEVfxB_T5ew7f9jH9L_bLrfNsEcqB1BH5iwnn89gqIbx1ngOF1IELcDwowpzJQe8KrF8YvzwUTrIquOxm8MMxsX5JvfSE2KDnz0kab1jeGdEVp4l3KO2wI9se3oGViu3i9UNGgUKw2yIPZg=s0-d)
[sin^2θ + cos^2θ=1]
④ , ![[tex]1+cot^2 heta=csc^2 heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_uKQLDydmLzyiIS911y_aL4Rb_aPyEA8zrlXtpWdNO_DFzXpsZ2CT_j2Z5KvrHLvehuwpj2xZiQtMwbk392BC5CfxnSMtVpjEqBV1FEkBKFymm56ioNb3MhzMyZJ6WBdpTJ3ZusNWJ2RteIy70cA5g=s0-d)
[ tan^2θ+1 = sec^2θ, 1+cot^2θ = csc^2θ] | | 9분 20초 | 21쪽 | 예제1) | [sinθ+cosθ=1/√2]일 때, 다음 식의 값을 구하여라.
(1) [sinθcosθ]
(2) [cos^3θ + sin^3θ ]
(3) [tanθ + cotθ]
| | 17분 29초 | 22쪽 | 예제2) | 이차방정식 [2x^2+px-1=0]의 두 근이 sinθ, cosθ 일 때, 상수 p의 값을 구하여라. | | 20분 6초 | 23쪽 | 예제3) | [sinθ+cosθ = (1-√3)/2]일 때, sinθ, cosθ 를 두 근으로 하는 x에 대한 이차방정식을 구하여라.
| | 23분 50초 | 23쪽 | 여러 가지 각의 삼각함수 | (1) 2nπ+θ의 삼각함수(단, n은 정수)
①![[tex]sin(2npi+ heta)=sin heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_v_nnUjjoHurJ0dWa5pw1KvBYgT7bKbyaL5n10ZiMNitlFDfTYPKPGxGmCYFF-go4yIrX9ZK1JG7Q_USwC3fg7EuQTYS8o5VYw4rq5nhFa_hCHKS3ctZzpSznz4uFqCwR_Sz8WqvgQhy38Ulrnyfb0Bi2KzxXU=s0-d)
[sin(2nπ+θ)=sinθ]
② ![[tex]cos(2npi+ heta)=cos heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_uVxXzi-NTv2nw3yj7AUyrvbqwEvwUd2l6pVnxW-H7lwWXOaHn5TxQbyvEUaIcqEUUivUq6ZHtpr7_VMMrcS4Sv9_MUUqU9XgcE2tzPy7J4Q0lFTba9NbKP2bFPDLqBCbF--zT7QdrIw9L_f5vfCDbt1w=s0-d)
[cos(2nπ+θ)=cosθ]
③ ![[tex] an(2npi+ heta)= an heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_ugmskJyRjIrdgk2Bc6ARkkUxMQuiXKPV3Vk7aMx63y5pS0Vpd3bczE7uxYiaqiq0q1Pw_ia7D8k5b1F0cW0d02QG0rVX7JCCbqJZhg6nOYCz-t-sL2oiR6JjcpHuqsHzSHtT-ofmUER8LbeBJRRx55d_TCCRs=s0-d)
[tan(2nπ+θ)=tanθ]
(2) -θ의 삼각함수
④ ![[tex]sin(- heta)=-sin heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_tWngYD-Re8l_mh4TnxHb34dgezGZlGO7MVbDkDxdlnQE6Fp8UWpB0JIsk432U8oN32as4xB8-1BW1zu8B_OfTxVHgV3sf50iDrJIT747Y4T3TjItRARVXMVoFvZULPaSlmke7KSQwtG2SWyHaaiNo=s0-d)
[sin(-θ)=-sinθ]
⑤ ![[tex]cos(- heta)=cos heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_sMuE4x74ZXiI5CxIfVN78whx9_o9Ssn2MwHFUmBWuVp1Ix28_UQCAucyxnLWyZpPLOjRHtsIkwLkNanT3FuaX0b4DiIqH8f6tRdAH90EQkVBl_BGlGBRNxtsgvbC7-h4YpSE2rmfV2Zkn6Gg=s0-d)
[cos(-θ)=cosθ]
⑥ ![[tex] an(- heta)=- an heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_txTgjLeSlzjM0sQd8oREMajfa3bRLM9mabuwykUP_DPjIpUU1Im7XDdV5zlXPkkPlmT1r_iV5ocq7p-Vkq0xSQc33OSaOZCxphDXVFZ3RbAQvLOLxOiXQZ8GS49ojC02AjI9InJUA3In24u8nvGA=s0-d)
[tan(-θ)=-tanθ] | | 51분 6초 | 29쪽 | 예제1) | 다음 삼각함수의 값을 구하여라.
(1) [cos 15/4 π ]
(2) [sin 3/4 π ]
(3) [cos 7/6 π ]
(4) tan 150° | | 55분 15초 | 30쪽 | 삼각함수 사이의 관계 보충설명 | | | 1시간 1분 | 30쪽 | 예제2) | 다음 식의 값을 구하여라.
(1) sin50° + tan110° + cos140° + cot200°
(2) (sin10° + cos10° )2 + (sin80° - cos80°)2
(3) tan(20° + θ) · tan(70° - θ) | |
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