진행시각 | 교재쪽 | 제목 | 설명 | | 14초 | 20쪽 | 삼각함수 사이의 관계 | 삼각함수 사이의 관계
① , ,![[tex]cot heta=frac{1}{ an heta}[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_sLiOFOM-7UBsdCfnFBclZ8DnlgBXga0icDl5KM9Jgw02-69aTjFu7y-8ZX_GUubD_SGjmilXBWy5XyFRgFxgceg6ScQOIWtQnQHNU4cgpl9k6M_-xGGEqDqI6tAqb9khkn2rfmvVIZzI7zUZa4dBdOeSn9F5bHvoClYywRSPg=s0-d)
[cscθ = 1/sinθ, secθ = 1/cosθ, cotθ = 1/tanθ]
② , ![[tex]cot heta=frac{cos heta}{sin heta}[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_sFy9-ZE4bSfazq6mI6QFUMQNwuME-05tI2yNloc9_NnyFBHr5_21x2JYkqXDQuBcPNxCQy8Qr7il3LssyRuPa6nn9vYAvScFOJK0CBqtkb87ZH6FQaQQ0NC1m5tr6eUN2mm8S9IGgeL11m_3E4s9beaOuGDuEQfK-CUql9J-A_i9kvcNyKACqFK2gg1w=s0-d)
[tanθ = sinθ/cosθ, cotθ = cosθ/sinθ]
③ ![[tex]sin^2 heta+cos^2 heta=1[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_uDrZqmm9QiK5PKf29nUQbeAdIgSADIC7H1Ivwvlqc7OJmbqcB9ZY8FcYHOtOSfXS5rj9SEF1AodkyrGVn2PKTVGEwsR24Q5u4Ill8CUM2gEzUFij2PKuhRbiGOrOQbSW1QFqb15Ob_BGZWh0mORg9EWhWRZwA=s0-d)
[sin^2θ + cos^2θ=1]
④ , ![[tex]1+cot^2 heta=csc^2 heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_s30ZzTbkCSSklzgn6qnPqGJmPAMeCoX04FhldLP_PBor0ZOwVhFaOzUft5QuGL1FUowZ6ZJPBUlVNu8oIvROl9eq2Hzp3456RD_1icj0ifrL2TwZcFtWGQaA041pztcClerZCekC7xHUyMoy2liMI=s0-d)
[ tan^2θ+1 = sec^2θ, 1+cot^2θ = csc^2θ] | | 9분 20초 | 21쪽 | 예제1) | [sinθ+cosθ=1/√2]일 때, 다음 식의 값을 구하여라.
(1) [sinθcosθ]
(2) [cos^3θ + sin^3θ ]
(3) [tanθ + cotθ]
| | 17분 29초 | 22쪽 | 예제2) | 이차방정식 [2x^2+px-1=0]의 두 근이 sinθ, cosθ 일 때, 상수 p의 값을 구하여라. | | 20분 6초 | 23쪽 | 예제3) | [sinθ+cosθ = (1-√3)/2]일 때, sinθ, cosθ 를 두 근으로 하는 x에 대한 이차방정식을 구하여라.
| | 23분 50초 | 23쪽 | 여러 가지 각의 삼각함수 | (1) 2nπ+θ의 삼각함수(단, n은 정수)
①![[tex]sin(2npi+ heta)=sin heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_ubPunJ5rZQEgs0whiS4_SE5IswKWFbZg4goiyxuyXdN7cXrD3rQp50aZugBWNEa16tI6XGLc-jby9QS0luxXHyd_aWB_UCTtp0BKZ66tMJdZjZooIFvnHhXlFSki_r_4nDltPuIsNOmIyZxzt2SCP_KSBoFxQ=s0-d)
[sin(2nπ+θ)=sinθ]
② ![[tex]cos(2npi+ heta)=cos heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_tERya6UzbJ-QpRdwM0_AAH9HedRbhQti5euJfLLIft11Iy4HgAt64OcyHAvF1jhbRcT7gRNWPfJVZAQvBHy6-MlkrdVPzDluc1CakPAX4vIzLwEsSmru1i5uge-nLdztZrztrcx3k52gZPFC3feylUnw=s0-d)
[cos(2nπ+θ)=cosθ]
③ ![[tex] an(2npi+ heta)= an heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_upNPffnuKv5aTiZMTMUbEao_K4W-bwlFZolNi5wn5hN_166SWcc09n8opi7VtNjwe6MhZK0pwx5tZIJG3z6rki8myHbqbf5D2xHLGSXfH3vkR6TRzyKWtCR2E6AVypXR4uVRBNiFvtYVuYf-SycDMw0jSrtqc=s0-d)
[tan(2nπ+θ)=tanθ]
(2) -θ의 삼각함수
④ ![[tex]sin(- heta)=-sin heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_uaBWHe6loaot0MOu9RkKYl8JH_KvHUb-3eMoK6jjU4Xxt-v-BaZ-FtTrGjo0oECXvA6mSixOXyi8gRxidil_1RumNFv_nI2Zw2BOCTxjleLQWJEup_Xn1D7UyXfvvz12wTfFbLoVx703RR8mZYp6k=s0-d)
[sin(-θ)=-sinθ]
⑤ ![[tex]cos(- heta)=cos heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_s2X_vfv6vAlizIRqs1xaePUAaJr37524lFaOgKESEBUJFsuDiQslN7jsir1kCFwLOzKsB0tf_LF5ocaoZKhXQagaiNqymEfU1p-ty88Vb6z-loMLoJIdaoq6qzMGeWwcNdwIbZ6fCZnwB2zA=s0-d)
[cos(-θ)=cosθ]
⑥ ![[tex] an(- heta)=- an heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_sGM-AfV-ewlUtzm-VCSytKcka-VBkj--3iBfTkGVhDxT62DsElTGN5uwa6JbM8TZRNw_PVsRXGYf_Rxd4MDTrl0vQWGNX_xztZZYzI9IZIpbWofxKx3hLsMLi-DORVkVZEnEicgq7BxQ_E6TW4GA=s0-d)
[tan(-θ)=-tanθ] | | 51분 6초 | 29쪽 | 예제1) | 다음 삼각함수의 값을 구하여라.
(1) [cos 15/4 π ]
(2) [sin 3/4 π ]
(3) [cos 7/6 π ]
(4) tan 150° | | 55분 15초 | 30쪽 | 삼각함수 사이의 관계 보충설명 | | | 1시간 1분 | 30쪽 | 예제2) | 다음 식의 값을 구하여라.
(1) sin50° + tan110° + cos140° + cot200°
(2) (sin10° + cos10° )2 + (sin80° - cos80°)2
(3) tan(20° + θ) · tan(70° - θ) | |
댓글 없음:
댓글 쓰기