진행시각 | 교재쪽 | 제목 | 설명 | | 14초 | 20쪽 | 삼각함수 사이의 관계 | 삼각함수 사이의 관계
① , ,![[tex]cot heta=frac{1}{ an heta}[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_u8Mk5EEMlN0LL9dYRW_YCeZT9AJKeezf3oQF3D3wrwg6qKaZl-zpyeV_0zWsAIMkTmDc9XkYSx9UlufrTfy3hBoo2z3xntJzxiA4sGwuT-zBVEL7TFtiPe5HloD-yWXSziLzH2Mjk9SyIkOs5_7f0kftSgVoU9yRcZbYtaNyA=s0-d)
[cscθ = 1/sinθ, secθ = 1/cosθ, cotθ = 1/tanθ]
② , ![[tex]cot heta=frac{cos heta}{sin heta}[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_tdbCvvPdaa-6L0PegKNP7_v0syBzgmchuFg7PnG0cgffG_rNgmHCiXA4iSYUTLP1JndrjVy8LNMTHoJukTxvWCGh9EcF27c0BnLZ-ClFGvcpbpovgij8qIJoEiXtTGJ8Ads_j-l43zdOxnh4n3efkenMCvZWY1ri0imeN8OjX5T_BqN8ntTRgKvfGnPg=s0-d)
[tanθ = sinθ/cosθ, cotθ = cosθ/sinθ]
③ ![[tex]sin^2 heta+cos^2 heta=1[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_sOUvqDADdJsKR2kmzacu-HDGqczCuLY-uNf5Bnim0SwSmid_Z2R9p7AkhijsdoHAS_w_5xK_1Ab7gOlkrIugbdvL8wrxZ-Qhi6uW_V5-R0qpMw19Sbgux-ryi6OyoAFTeLDX4M2Kkf8KnIhegqmcM_jZds_mg=s0-d)
[sin^2θ + cos^2θ=1]
④ , ![[tex]1+cot^2 heta=csc^2 heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_tFcWvglhV4G0vxxREmu-ia0FpnCJf_TB_vw6g7LbthmCYilcHV_zKnuE5o0TTLRLMZj3qG2wBx4hfyrWvY_GAYGXEBfUgSTzyhoz5SgdFZcrG4FTIxAN544l6E974aNX3F1eGNqIgfEdddv4mY0nY=s0-d)
[ tan^2θ+1 = sec^2θ, 1+cot^2θ = csc^2θ] | | 9분 20초 | 21쪽 | 예제1) | [sinθ+cosθ=1/√2]일 때, 다음 식의 값을 구하여라.
(1) [sinθcosθ]
(2) [cos^3θ + sin^3θ ]
(3) [tanθ + cotθ]
| | 17분 29초 | 22쪽 | 예제2) | 이차방정식 [2x^2+px-1=0]의 두 근이 sinθ, cosθ 일 때, 상수 p의 값을 구하여라. | | 20분 6초 | 23쪽 | 예제3) | [sinθ+cosθ = (1-√3)/2]일 때, sinθ, cosθ 를 두 근으로 하는 x에 대한 이차방정식을 구하여라.
| | 23분 50초 | 23쪽 | 여러 가지 각의 삼각함수 | (1) 2nπ+θ의 삼각함수(단, n은 정수)
①![[tex]sin(2npi+ heta)=sin heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_uZA7tmJu4Kk5O1yyKnETWV-gr_f1AIce-xEKRZDeH61AheJZfd6M5khDVs99IwD4b4S_CcEiyioWLTlq_ighmx_wdOmzft7SSTtgdzjmOqrAprfSAwxBA4mqfJBHWxnMR6THy3hC92C29g9GnaPPqPi3d2sz4=s0-d)
[sin(2nπ+θ)=sinθ]
② ![[tex]cos(2npi+ heta)=cos heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_uqmVKHOEYp3DiTsMkYgSMHO2T1itU8AQL5UldL0hCAQwRkuty6jgLE7fDJ5Jb8d0D4zWsGrNtYx7NUvNt8Wbwg6C3Eq52phYEUbEkz1FdeL3LAtmiODZbT9gpw__-JBQFwLzcxG1e-xYK52-vly1UIaA=s0-d)
[cos(2nπ+θ)=cosθ]
③ ![[tex] an(2npi+ heta)= an heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_tWIVy47SBBu8CK2uCl7Qr6z2sf-efw2VkABoUu5XTnqAirl76C8Ck0LcxOXN56nVVO-bhTBlY24q5ocwgPpzOZPZaKRB62sdGs0zXjkAZaCKCW1u8U9OjIdtT2TKX0vmWa9C8JNT77y9HgwLJwgY_BeGoGn1E=s0-d)
[tan(2nπ+θ)=tanθ]
(2) -θ의 삼각함수
④ ![[tex]sin(- heta)=-sin heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_s1g8EsXss42Uqrd45IwISiizkHcA4U8_WmY51JfD9wmi3MVH-BMxkkZpj9SMUj6tRDf9gNeuEPGdOnWzHAXGM7P4Q5aZYmFRvvQxuruWdOXngcSaX4yKJ99cmiL1MM2tIC_EpXZlJ7JFhHCyF_-pM=s0-d)
[sin(-θ)=-sinθ]
⑤ ![[tex]cos(- heta)=cos heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_tHoPyHDRrbw7dbPGFWGc0LLnAiwKesy4OmeE16fkEK1Asievb9HPKFNPJtKczLupvkNPvoSTPX-wayECFfPCMDjp4fzFQ8TTuDw61ZWSc5Q_nBG1djSwGQaSb4iTL_LJuFG50_OCvrF5o31w=s0-d)
[cos(-θ)=cosθ]
⑥ ![[tex] an(- heta)=- an heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_sU6ndbl99cell98xOfoif7BHw4OrX8cdt4cRFL_YJovqorPDpT3oMU5J0Fd2NjBVqSP07tElNKnK_ySMJ7ZMO6ffoqGLBqwfDNNbg7GZU-KgKGMOMScU5ARWK349z9QxzyTudXdXzzvjwEtMVBOQ=s0-d)
[tan(-θ)=-tanθ] | | 51분 6초 | 29쪽 | 예제1) | 다음 삼각함수의 값을 구하여라.
(1) [cos 15/4 π ]
(2) [sin 3/4 π ]
(3) [cos 7/6 π ]
(4) tan 150° | | 55분 15초 | 30쪽 | 삼각함수 사이의 관계 보충설명 | | | 1시간 1분 | 30쪽 | 예제2) | 다음 식의 값을 구하여라.
(1) sin50° + tan110° + cos140° + cot200°
(2) (sin10° + cos10° )2 + (sin80° - cos80°)2
(3) tan(20° + θ) · tan(70° - θ) | |
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