진행시각 | 교재쪽 | 제목 | 설명 | | 14초 | 20쪽 | 삼각함수 사이의 관계 | 삼각함수 사이의 관계
① , ,![[tex]cot heta=frac{1}{ an heta}[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_sKHmzG-gRyhGpQIN47Z9nUJk8GLfrvYKtucHKuQYaQ0zgvtAeBSG8yjK_PY2PFQYyoGHesvTaSQyDW2lp3IXnyN-fj87bRqAsyEZ4IP1wEHDkr5FCVinv0lCsLmMoi6Z7IjIF7qiOZdvEm8eiqhJZV1jD_BTn8tSkNrwgtXvY=s0-d)
[cscθ = 1/sinθ, secθ = 1/cosθ, cotθ = 1/tanθ]
② , ![[tex]cot heta=frac{cos heta}{sin heta}[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_vMMqCzPByHOVp0JdOZSR14BI1-vGnTCguVN4Vd3ueRy3Mawk4JxmXklXPe75yLDxT13z7SUdp5OmfIVDh-zNOuy1ynpBAIhROrW93c5giRoU2cT652RaYrLrgWP1a54KCGztMR3kaFz-gUmngFvGEXJ9kFmOF2fk5Fn0muCCVmzx4b6pKTA8DzTjzttg=s0-d)
[tanθ = sinθ/cosθ, cotθ = cosθ/sinθ]
③ ![[tex]sin^2 heta+cos^2 heta=1[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_uPXJQ17rUl7UwemKnmi5S4sloJpWwL8DSJlc3zqh-Qk-seCb5vytC5AYtAaBbEdY5Uh1yH4pDU5ZeQ_t7VnsrKDDvkw4vjujLnyCVVf5_7XEuvIT-ks-nNdGjgfXf39kOjE4x0C1HhFA9lHyDei7gY9k9_55M=s0-d)
[sin^2θ + cos^2θ=1]
④ , ![[tex]1+cot^2 heta=csc^2 heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_spOH_r8ngC4YxEfFuPvKjXNv2Hg8O9xuSvMBdvsZIrP-pjsESV-tG8h9JQmincz3BfIp1kvjtq-48F844K-pD36OfTAvTuir4whA7fwNwnrg7Cpx_DZQcuS5dSYmGkLUzF10i6qWi-bxaUHPozDp4=s0-d)
[ tan^2θ+1 = sec^2θ, 1+cot^2θ = csc^2θ] | | 9분 20초 | 21쪽 | 예제1) | [sinθ+cosθ=1/√2]일 때, 다음 식의 값을 구하여라.
(1) [sinθcosθ]
(2) [cos^3θ + sin^3θ ]
(3) [tanθ + cotθ]
| | 17분 29초 | 22쪽 | 예제2) | 이차방정식 [2x^2+px-1=0]의 두 근이 sinθ, cosθ 일 때, 상수 p의 값을 구하여라. | | 20분 6초 | 23쪽 | 예제3) | [sinθ+cosθ = (1-√3)/2]일 때, sinθ, cosθ 를 두 근으로 하는 x에 대한 이차방정식을 구하여라.
| | 23분 50초 | 23쪽 | 여러 가지 각의 삼각함수 | (1) 2nπ+θ의 삼각함수(단, n은 정수)
①![[tex]sin(2npi+ heta)=sin heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_tl_Adaa0vAa5xSVFoC9x4n9PTvZ-BXKCyRjZlTWFIazvamWpdYynKl_KFxmu2zcUXv6XrAH2_EA3arH-cYEYgNaAYeOJ-f_06CAOEdC_m20YDXoV98x0mTv96mOLbSSrgR8kKe1mcPcUcRkbo_2Q32uBpDyV0=s0-d)
[sin(2nπ+θ)=sinθ]
② ![[tex]cos(2npi+ heta)=cos heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_s1WS473ZqrLYA-TE3bCUkxnjE8e7k8vyKXi9FgxNx_TFadwUDM-Lr6jZEM-chatd72h_8FgAy41g3ggwd9PuDMYGBAaQY-rNjQWAcli3V3nUiMZ8jSE2ASobJDQPgsDHBvFMMiyckuhNRo74ptBt_pig=s0-d)
[cos(2nπ+θ)=cosθ]
③ ![[tex] an(2npi+ heta)= an heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_uplX6FPVrtbHIA5nKUhgAM3pSZURKOIOtCYeWMuyRzHgq0vzsYdvdfPO-8UQvi2stSpjZKbSulzyheuyqVQJre0NtWEL0oxG7TX2UpXXp0QRYedHv589U7WgsS293E9cAwiMklwesqeK5PH3Zrohx2G7gzQxU=s0-d)
[tan(2nπ+θ)=tanθ]
(2) -θ의 삼각함수
④ ![[tex]sin(- heta)=-sin heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_upCjpAB2wWpYdWxu2nNFsM8pJawKq917Ge6XGmVNywX0apxdXXxUXhBL0Yuu06MZFlK5QCX-fYwstr8JDEGioIhyayFRRQDojTvKI8q-SVsPDeVQS-ctuX5Dn3B-hW93-yNDQ7HRd0NjEfsMANctk=s0-d)
[sin(-θ)=-sinθ]
⑤ ![[tex]cos(- heta)=cos heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_u655HcXKqOgbEF0NXxnS2pqSjN_SBOSmSAct_J1-oE1TTKEk1URjDNzZdqtNZqQ_k4RhC5Xx262qwafexvy6IlHa4kIG1QHmKDcoTwdGFVP-Lsi7rqOyguiBQNo3nd5_S24SSzbVGBLCqgNg=s0-d)
[cos(-θ)=cosθ]
⑥ ![[tex] an(- heta)=- an heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_vd3YDytDOPwNUSuJQf5A7e7kaDaPRVyu2hFGPr2oNsfwwWzQglteLqgy1E1F152D3hRw-8H0gxSy-60wl_3htQKle894DOLmnl-WcOe6FfEAvibRwOvsEPND7dywtk96DxtfzUS285blVMswK4jA=s0-d)
[tan(-θ)=-tanθ] | | 51분 6초 | 29쪽 | 예제1) | 다음 삼각함수의 값을 구하여라.
(1) [cos 15/4 π ]
(2) [sin 3/4 π ]
(3) [cos 7/6 π ]
(4) tan 150° | | 55분 15초 | 30쪽 | 삼각함수 사이의 관계 보충설명 | | | 1시간 1분 | 30쪽 | 예제2) | 다음 식의 값을 구하여라.
(1) sin50° + tan110° + cos140° + cot200°
(2) (sin10° + cos10° )2 + (sin80° - cos80°)2
(3) tan(20° + θ) · tan(70° - θ) | |
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