진행시각 | 교재쪽 | 제목 | 설명 | | 14초 | 20쪽 | 삼각함수 사이의 관계 | 삼각함수 사이의 관계
① , ,![[tex]cot heta=frac{1}{ an heta}[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_u_sJ_EOOhJiw_N7kRyatLP54Dii6IAPDr42q9EdFa9rQvx3-XRX6RX_MwixI0Rjdd380Omhwf-zhcwB_jNAycSq1iqkZdQxFBxopmpre-mmiPc2z5NyB-S6mKra0t_o8fqubgXavwKs_WqoAmrthpY3DOgdo04d_YBkb1QlCc=s0-d)
[cscθ = 1/sinθ, secθ = 1/cosθ, cotθ = 1/tanθ]
② , ![[tex]cot heta=frac{cos heta}{sin heta}[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_tbQ3g9qllATC6eZgqyOu6kx3vrN8DB6dwudFLqPKqzn1HaVfPXe8hNUfmkv-xYIHM4XycewtkJ4SrYGsLxM9w8Ga7bqO_2HHDzGK33tZsfRXIupR5palSfYIbg7o7cU2Tdl9M-8G4AB02QU0ayjSrS2Yzx1R96CmV55tzF2_8cYObp4YcfjPJLiLVorQ=s0-d)
[tanθ = sinθ/cosθ, cotθ = cosθ/sinθ]
③ ![[tex]sin^2 heta+cos^2 heta=1[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_uSsb0JM-0Bfv511kVEEpKS2nPqxMWFzZb-QySymn1QJQehU_c2vEKp-jcVe58QhrtZk4tL2z3Jb6dWFYeQHqGj9Zo13_ZF7yjMLIDr9XmcYF0Kk03ZLiLtB9Pb4mXhH_K_6p7I_CRsjWjc9ICuKW9PdejILcU=s0-d)
[sin^2θ + cos^2θ=1]
④ , ![[tex]1+cot^2 heta=csc^2 heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_u9j1WOyHLa2zTuwdZLPnTC4PTtarysg_78KF-RIBFLnhuxsapKh1EZBTJoA-vIRShMQOXiwyScvpv5NAsYSFVtTZ1PQxdk9JoyOMz3oSsZoPTlPrrr6B5pTgWoySkr430OUx3u6X5yd2bB6fpUoHU=s0-d)
[ tan^2θ+1 = sec^2θ, 1+cot^2θ = csc^2θ] | | 9분 20초 | 21쪽 | 예제1) | [sinθ+cosθ=1/√2]일 때, 다음 식의 값을 구하여라.
(1) [sinθcosθ]
(2) [cos^3θ + sin^3θ ]
(3) [tanθ + cotθ]
| | 17분 29초 | 22쪽 | 예제2) | 이차방정식 [2x^2+px-1=0]의 두 근이 sinθ, cosθ 일 때, 상수 p의 값을 구하여라. | | 20분 6초 | 23쪽 | 예제3) | [sinθ+cosθ = (1-√3)/2]일 때, sinθ, cosθ 를 두 근으로 하는 x에 대한 이차방정식을 구하여라.
| | 23분 50초 | 23쪽 | 여러 가지 각의 삼각함수 | (1) 2nπ+θ의 삼각함수(단, n은 정수)
①![[tex]sin(2npi+ heta)=sin heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_t9nFXHsDaZmJdXyeOA0yPTpyv6Bs7owkHvzlNoL0oyJGlnYI1aOdQe74psUGFPRX1HbwnMaf4kpSDwoXiW-mLvUAswYR2RS6egg-qbpcoFNbzOh1htY1Rbgi1CymD0gF464DNOrepKDvyu9RD_-i9mijgX8oE=s0-d)
[sin(2nπ+θ)=sinθ]
② ![[tex]cos(2npi+ heta)=cos heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_u0tLz1eB2t8bkO8TrJzXM0GvkKKHQ-QtAdgFpTHR5VVxZWf4_9h1gW6tf9yHJ_AovL6zF8VeBqyfMk9D7KyEC893LcZTOZlJoZzbjiOUnQjVWbvwode8hNA0Dau-vkEhrRQIYHGiK0iE-5MGVH4I61wQ=s0-d)
[cos(2nπ+θ)=cosθ]
③ ![[tex] an(2npi+ heta)= an heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_uo3CqhXeAg-7b8Cu0PndLix0gGhBzoD5DTN8qKHpWskuFwNrEZt1F7jGteY8VzRtbxM0k1YOXUhZvXjyfW6OZMebXtAofcCjl48wUI-m0nt52r_0Wn6LK4oAN_z-5CwjSny0LvXW7XRi75T4OH-e35SleWsko=s0-d)
[tan(2nπ+θ)=tanθ]
(2) -θ의 삼각함수
④ ![[tex]sin(- heta)=-sin heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_v2pki04-ZMT25ri5lHuQ9bTp3tSTzRP0IL2bpjeY1wjCWHNhhw9PvQtilHR_gFfOnXPuP4bMV37RQzhZTR9YsP6Q4crZ3Orp5VC1OmBk5OX2VY5prb2L1XvjScdkLYyn2o02Kzu71z5bNh8a6JzrA=s0-d)
[sin(-θ)=-sinθ]
⑤ ![[tex]cos(- heta)=cos heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_uRlkATgK9ZkazQIQqjvFTnMfFECpG-jOoU6yfZgTFjX1mHivMdaUP3vesq4-277ln9vufzsus2UNEnQh9qxjDeHngRrCxlNYhm8oRR_mxngfhA44oxiCJkgPxukLmHrbmTY3nCt1lNOa5nXw=s0-d)
[cos(-θ)=cosθ]
⑥ ![[tex] an(- heta)=- an heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_tTKz4iJK9_Ecv5S6_H38msDDmLhPTnVSVOYi0R79KWigX7LA8gHruOuU_wx6gmBMSUsq5YzLxs6QGsVaZ2sOnaf8IQ-AZ1Z7FYeNhJdu4UECoxBv3QVY2U9mPpsfUFCgvrP06312O7RVg17FAExA=s0-d)
[tan(-θ)=-tanθ] | | 51분 6초 | 29쪽 | 예제1) | 다음 삼각함수의 값을 구하여라.
(1) [cos 15/4 π ]
(2) [sin 3/4 π ]
(3) [cos 7/6 π ]
(4) tan 150° | | 55분 15초 | 30쪽 | 삼각함수 사이의 관계 보충설명 | | | 1시간 1분 | 30쪽 | 예제2) | 다음 식의 값을 구하여라.
(1) sin50° + tan110° + cos140° + cot200°
(2) (sin10° + cos10° )2 + (sin80° - cos80°)2
(3) tan(20° + θ) · tan(70° - θ) | |
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