진행시각 | 교재쪽 | 제목 | 설명 | | 14초 | 20쪽 | 삼각함수 사이의 관계 | 삼각함수 사이의 관계
① , ,![[tex]cot heta=frac{1}{ an heta}[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_tZLLfBFeZIH4wWtgbG_wG8MpB2gq8kp4spcDMcV51n4fKvlCNdLtxWgdpim-DrLa6l7xV1x2bIIOyi0ZT8TK4e8-EMTQw4i46mP1LjPQoXuDhoWYgZSLTcqfIWDTgFJFqr4oJnEcbwP9cO92xqxap9zgFSFzGaT9iD9iFOYP0=s0-d)
[cscθ = 1/sinθ, secθ = 1/cosθ, cotθ = 1/tanθ]
② , ![[tex]cot heta=frac{cos heta}{sin heta}[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_vpL1H8rAYJ1AOVBgYhx8Ms62_lDHbM1sqRrHvB5-1NUuY5DfpHoLoju5JPNJDRlm1HpBXhnPOydMX5qEkI-reSlH_CgkXZ5Ncje5fv-XSszdf47gptFvAhJ-ZvQyQGFG6JeJ-GI3-5-mVvkRu59jPUDTXXZPSAakaQUr8bS7ZBJcYwRQQv8C6ik4x49w=s0-d)
[tanθ = sinθ/cosθ, cotθ = cosθ/sinθ]
③ ![[tex]sin^2 heta+cos^2 heta=1[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_vgJ9OAp4UbACz9_OhTmOoIpAwIDFDeg7RUvnIM7z1X8mewqQG2HGfQW30K43DytVqpyyV3lDPnsuXzKyqLKXXQCfUACkKOzNKnHrz43szGZgWZX_QAqqxIInW_7CyBGQoVmnZ6wJBnnTTe2T-E2v3Raplhg1Q=s0-d)
[sin^2θ + cos^2θ=1]
④ , ![[tex]1+cot^2 heta=csc^2 heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_snB-wg16InvpEvUQ0FJk7_avPprglHRk7p864uSUJlW6WycrhGUWVujUoKQ-KqexUiDKB2iJ7BMB7EXtYmJo9QjqOScImZyRfMhuLNZl5wgOL18OyCjGWAVyQXUD3Qh0lD_13te1SZLevCMOR-y6U=s0-d)
[ tan^2θ+1 = sec^2θ, 1+cot^2θ = csc^2θ] | | 9분 20초 | 21쪽 | 예제1) | [sinθ+cosθ=1/√2]일 때, 다음 식의 값을 구하여라.
(1) [sinθcosθ]
(2) [cos^3θ + sin^3θ ]
(3) [tanθ + cotθ]
| | 17분 29초 | 22쪽 | 예제2) | 이차방정식 [2x^2+px-1=0]의 두 근이 sinθ, cosθ 일 때, 상수 p의 값을 구하여라. | | 20분 6초 | 23쪽 | 예제3) | [sinθ+cosθ = (1-√3)/2]일 때, sinθ, cosθ 를 두 근으로 하는 x에 대한 이차방정식을 구하여라.
| | 23분 50초 | 23쪽 | 여러 가지 각의 삼각함수 | (1) 2nπ+θ의 삼각함수(단, n은 정수)
①![[tex]sin(2npi+ heta)=sin heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_suWZsYaaNV8nAcI6cQRV6-pBF-rmSi2mg28zMPU-uCasH4UETAlkIUpiIG5sU4xRmlLZGZ2YWsLvABjGkPtVmRkXadB1Xwzz3sw5Qzf1Hb7sAyQFPtqVoEfhpRwTd9ODZwaL8gtDCOWMgZHmOlxdloStcvraw=s0-d)
[sin(2nπ+θ)=sinθ]
② ![[tex]cos(2npi+ heta)=cos heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_sDunjQJErmhV6SN7d3P-4af7PoFAIe09wSC16_Tkhtq9uzPkaiJ2s0RVv7iMW8FyrRfKWKIkJG7X8MoS_O8mthhnHxKVczApAxRkDytkzpLNaFmy6qHRO6T9BeDRxJNWxgl9264uBDSwANOnafNiLFwA=s0-d)
[cos(2nπ+θ)=cosθ]
③ ![[tex] an(2npi+ heta)= an heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_u9eIHw6RvHaGmNTJm3mySFoRkGqN9b4h5xzVyOIhHt3F8nv8HQDv5eQYLM6yqiYGy0W6kkFeeDD87PTC2-xVTl69QWT08zagBQ_XmxYOcBzkQGktuWRDIx5kECCwQAMEzUcIqWG1bqJ9O2xCOuwK82PML3Hks=s0-d)
[tan(2nπ+θ)=tanθ]
(2) -θ의 삼각함수
④ ![[tex]sin(- heta)=-sin heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_uUtXoATLPK1a6wxXvgIKOY8dvQ5Okt3unNbmXejmcUcYJi68aKHct79dxJv-f7Ymb6uOhxwFmSN1DEffjhPdT_s8z9BkDgpb8A5pGfJVvj5L_2fAgXGA9UyTkNVOZ79zcV4hdXJKUt8nxLdFjWWqI=s0-d)
[sin(-θ)=-sinθ]
⑤ ![[tex]cos(- heta)=cos heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_tkeTc4fZWTYRjcC3-ZW-glARjZ9GtS-6nDv8WVh3DqG5_ZgK-SYKPFH7vVCAtrz6gSzgjM6J-HHwyYTg2U36U0J-smAlA_5Skx6xWh3JGDy4JFN6ATIM3iQ6aviYhZdJKZcezPaQ7e6A9VkQ=s0-d)
[cos(-θ)=cosθ]
⑥ ![[tex] an(- heta)=- an heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_sVqbnV2kNVspe-VUvlQpMfeiXC8mOpGJRgeOvSae3oE98NQvD-N-4VGF0jz-oLt4bxZHZ8HOQX1rvuDEGwPcitvUWK42Qf6dD6RoD_5H2PtlDkzYedZmZcIyTLpWztqBsIbfIBwSlOH5TKgZYnyw=s0-d)
[tan(-θ)=-tanθ] | | 51분 6초 | 29쪽 | 예제1) | 다음 삼각함수의 값을 구하여라.
(1) [cos 15/4 π ]
(2) [sin 3/4 π ]
(3) [cos 7/6 π ]
(4) tan 150° | | 55분 15초 | 30쪽 | 삼각함수 사이의 관계 보충설명 | | | 1시간 1분 | 30쪽 | 예제2) | 다음 식의 값을 구하여라.
(1) sin50° + tan110° + cos140° + cot200°
(2) (sin10° + cos10° )2 + (sin80° - cos80°)2
(3) tan(20° + θ) · tan(70° - θ) | |
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