진행시각 | 교재쪽 | 제목 | 설명 | | 14초 | 20쪽 | 삼각함수 사이의 관계 | 삼각함수 사이의 관계
① , ,![[tex]cot heta=frac{1}{ an heta}[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_uykX8trHnwYnDfRkZ-WAh5lZDGRdMRjm2S1PV_DisGRt9plflvuBnIo1sn33COkWIGRZKNnbNrE5MwUsdE4D7ys5th7po7ld4MO-ZXDTrOX5tFXFhFCKM2MC3alwl28t7FJoqHjsirFDlK0TqmmVb1FqfDE_pHXA1nCUowDv0=s0-d)
[cscθ = 1/sinθ, secθ = 1/cosθ, cotθ = 1/tanθ]
② , ![[tex]cot heta=frac{cos heta}{sin heta}[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_uOc3zzia4CIjwAX4XzjG-IXe2bQGh5F17Xx6JdnpYxhoF3T8DTgibSsht1jrDqhK9nAK_697GS08zVHEebCXFlxLx2DBNR0tZ-SVLglHoIi_VDnzQykCpFB97xhtVWfFOqW1pnTnSjmuUlr27OcUCHd9W3qRUPjzIh5Mv46E25nVAarMorqXlI5W049A=s0-d)
[tanθ = sinθ/cosθ, cotθ = cosθ/sinθ]
③ ![[tex]sin^2 heta+cos^2 heta=1[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_scxO8ssrCMwYZKV4ESVxAHVi2Fp3RhaiXkuuaFPXAt6fIiuhnSgOuNnrWCOeHV8RH4kY3aEMs-8ZAM3sCx07q1LBMKcXkXPzMIcPDJX5K8xIv06h9QlTwCxDC9t5qLyTPDPJQBfpWHuSHB_yruAJfeXHftXEA=s0-d)
[sin^2θ + cos^2θ=1]
④ , ![[tex]1+cot^2 heta=csc^2 heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_uJDHYQdbZHfzDmqiujE-otaWd9yBVm9U6lES0cgH3CuYxzARGkldmkR0vCnOSOG-5mrrxc-oVWhYQE2O1ne9LyXHOeBjr8weEQHd8Oq7qilWfz_SA-k3nlLbSpUTVP-WLG_adaOSazARgW82gC7o8=s0-d)
[ tan^2θ+1 = sec^2θ, 1+cot^2θ = csc^2θ] | | 9분 20초 | 21쪽 | 예제1) | [sinθ+cosθ=1/√2]일 때, 다음 식의 값을 구하여라.
(1) [sinθcosθ]
(2) [cos^3θ + sin^3θ ]
(3) [tanθ + cotθ]
| | 17분 29초 | 22쪽 | 예제2) | 이차방정식 [2x^2+px-1=0]의 두 근이 sinθ, cosθ 일 때, 상수 p의 값을 구하여라. | | 20분 6초 | 23쪽 | 예제3) | [sinθ+cosθ = (1-√3)/2]일 때, sinθ, cosθ 를 두 근으로 하는 x에 대한 이차방정식을 구하여라.
| | 23분 50초 | 23쪽 | 여러 가지 각의 삼각함수 | (1) 2nπ+θ의 삼각함수(단, n은 정수)
①![[tex]sin(2npi+ heta)=sin heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_uyubw5MLNpTmkpe0R-PF8W6hDulJ4UqnT6GctFbd_CYp-ADkzDZF6M4IfHrJPUloR41nAT5vFIgkBEvJz9rl2C-GXOisfR4tRCT0v2WfD2PFJhk03v-LH9fu3UkhyzGnprD-TYxqHzabaGDRCX7roA1vCuvi0=s0-d)
[sin(2nπ+θ)=sinθ]
② ![[tex]cos(2npi+ heta)=cos heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_vB6viZoiumN6WC39z4QhBbaVv78IAl5mRDZQODk6Vip715B7AqJY20B_Rsvbtqo1UkIa-DiNkKxPS87VsQoVwoVq0x7JMgT90LPLCqQg0tLRAqOTTpwA6cn7sJhq5xEvazAQFX0M9zzCAxGbAMJQtW7g=s0-d)
[cos(2nπ+θ)=cosθ]
③ ![[tex] an(2npi+ heta)= an heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_sXYUpx_gxXwrcCVLyf5iBsxcag0HIzYxuHgA23ZjnOSDWJ7--K0Jq4lejpq5tMj3DgSrhBYPmuN1yizBCLFFtLveEksm6VOGqPJM8rJgHJv1hC4NCOfK0ngwtp9XEnb6qNK9GYcoOu0ih7N6xRNT9F22wj4IU=s0-d)
[tan(2nπ+θ)=tanθ]
(2) -θ의 삼각함수
④ ![[tex]sin(- heta)=-sin heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_v82pXoIknjmL-bjOWqeHuMkGVEFmUqeWoMKS9TedHotKyWTDuWXoLMN_CLnQTbfgyCxMyAgqRnqJqIryJQIzEKAXtPTBI9Gp_1jbw6qVdG_tmmjhKNZhXfwPtQj1I1q_2zR5diAOMDzGDrsiFp57E=s0-d)
[sin(-θ)=-sinθ]
⑤ ![[tex]cos(- heta)=cos heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_s6Rra3JUV6xxPYn055Pra1GrOuFIrZIDAkvPtgz7pzm3jCkco6Mlf7f9pLM0FCg08AcoB2IVo5BiQjWe72S3P4v3jCd_dL-dMo_JfltzG4yEkOVLGWNvRnd05TZ7CoZkrVy4MrLMNJ9VMxrQ=s0-d)
[cos(-θ)=cosθ]
⑥ ![[tex] an(- heta)=- an heta[/tex]](https://lh3.googleusercontent.com/blogger_img_proxy/AEn0k_v_BjowGOTCY0WaucS275Bzr3u_bQgv1yIK4i97pwNQZJ2BWw8Gqhml1OeT8Qwd1tmvrdShyNAkpB_0y3QCLps-KSejsvSBE4t2g0Ay9nVx2t0GT5inq1KSnlSS9KDwzOH5AaZKvIK7PCw1SysJ6A=s0-d)
[tan(-θ)=-tanθ] | | 51분 6초 | 29쪽 | 예제1) | 다음 삼각함수의 값을 구하여라.
(1) [cos 15/4 π ]
(2) [sin 3/4 π ]
(3) [cos 7/6 π ]
(4) tan 150° | | 55분 15초 | 30쪽 | 삼각함수 사이의 관계 보충설명 | | | 1시간 1분 | 30쪽 | 예제2) | 다음 식의 값을 구하여라.
(1) sin50° + tan110° + cos140° + cot200°
(2) (sin10° + cos10° )2 + (sin80° - cos80°)2
(3) tan(20° + θ) · tan(70° - θ) | |
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